Suppose your vehicle is licensed in a state that issues license plates that consist of three digits (between 0 and 9) followed by three letters (between a and z). if a license number is selected randomly, what is the probability that yours is the one selected? round the answer to 10 decimal places (e. g.0.0123456789).

There are 10³×26³ = 17,576,000 possible different plates. If any of those is randomly chosen, the probability of picking one in particular is

... 1/17576000 ≈ 0.0000000569

what do you need me to answer?

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.