Translate the sentence into an inequality. twice the difference of a number and 3 is at most -23 use the variable b for the unknown number.

For the difference of a number and 3, you should do b-3 and twice that would be 2(b-3). For this to be at most -23, the inequality would be ≤. Thus,

2(b-3)≤-23

is the answer.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol