Elaine is taking a test that has multiple choice questions, each with 4 answer choices. she comes to a question for which she does not know the awnser. if she can rule out three of the choices as wrong, by how much does she improve her probability of guessing correct awnser?

Assuming There is ONLY ONE CORRECT ANSWER,

The probability of her guessing the answer without ruling out the choices is 1/5.

if 3 choices are ruled out, then 1 out of the remaining two is right, which gives the probability 1/2

now, 1/5 = 20% , while 1/2 = 50%.

Therefore her probability of getting the correct answer improves by 30% [ not much in a REAL test though :P ]

binomial distribution

median= 2

range = 7-0 = 7

how to find median?

no. of term=28

median=(28+1)/2=14.5th term

the 14th and 15th term are 2, therefore the median is (2+2)/2 = 2

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !