The temperature of a chemical compound, in degrees celsius, changes when the compound is exposed to uv light. the table below shows the temperature of the compound, in degrees celsius, x minutes after the compound is exposed to uv light. x 0 2 4 6 8 f(x) 15 15.5 17 19.5 23 write the quadratic function that corresponds to the given table of values in standard form, f(x) = ax2 + bx + c, where a, b and c are constants.

f(x)=0.125x^2+0x+15

Step-by-step explanation:

So, we are given the y intercept, and since we know c is the same as the y value of the y intercept, we know that c=15.

From there we can pick any two of the points given to us to find our a and b.

Let's use (4,17) and (8,23) becase they are whole numbers.

So, with b=0, we can plug it back into the first equation to get:

So our quadratic is

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42