Y+ 4(2y + 3) = 15 how to solve and answer ?

First, we have to distribute the 4 into the parentheses

y + 4(2y + 3) = 15

y + 8y + 12 = 15

now we can combine like terms and solve for y

9y + 12 = 15

9y = 3

y = 3/9

y = 1/3

hope this helped

Y+4(2y+3)=15

y+8y+12=15

(Simplfy)

9y+12=15

(Subtract 12 from 15)

9y=3

(Divide 9 from both side - 9y/9=3/9)

y=1/3

Answer : 1/3 or 0.3 repeating

there are infinitely many solutions.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: