Mathematics, 13.07.2019 20:00 leo4687

You're a manager in a company that produces rocket ships. machine a and machine b both produce cockpits and propulsion systems. machine a and machine b produce cockpits at the same rate, and they produce propulsion systems at the same rate. machine a ran for 26 hours and produced 4 cockpits and 6 propulsion systems. machine b ran for 56 hours and produced 8 cockpits and 12 propulsion systems. we use a system of linear equations in two variables. can we solve for a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system?

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Answer from: FlowerChild1229

No you cannot.

Step-by-step explanation:

Let c be the amount of time it takes each machine to make 1 cockpit, and p be the amount of time it takes each machine to make 1 propulsion system.

For Machine A, we have 4 cockpits; this would take 4c time. We also have 6 propulsion systems; this would take 6p time. Together it takes 26 hours; this would give us

4c+6p=26.

For Machine B, we have 8 cockpits; this would take 8c time. We also have 12 propulsion systems; this would take 12p time. Together it takes 56 hours; this would give us

8c+12p=56

This gives us the system

$\left \{ {{4c+6p=26} \atop {8c+12p=56}} \right.$

To solve this, we want the coefficients of one of the variables to be the same. To make the coefficients of c the same, we can multiply the top equation by 2:

$\left \{ {{2(4c+6p=26)} \atop {8c+12p=56}} \right. \\\\\left \{ {{8c+12p=52} \atop {8c+12p=56}} \right.$

To cancel c, we will subtract the second equation from the first one. However, this also cancels p:

$\left \{ {{8c+12p=52} \atop {-(8c+12p=56)}} \right. \\\\0+0=-4\\0=-4$

We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.

Answer from: linsey9201

Step-by-step explanation:

Given :

Machine A ran for 26 hours and produced 4 cockpits and 6 propulsion systems.

Machine B ran for 56 hours and produced 8 cockpits and 12 propulsion systems.

To Find : Can we solve for a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system?

Solution :

Let x be the time taken to produce 1 cockpits

So, time taken to produce 4 cockpits = 4x

So, time taken to produce 8 cockpits = 8x

Let y be the time taken to produce 1 Propulsion

So. time taken to produce 6 propulsion = 6y

So. time taken to produce 12 propulsion = 12y

Now we are given that Machine A ran for 26 hours and produced 4 cockpits and 6 propulsion systems.

⇒ 4x+6y =26 --a

We are also given that Machine B ran for 56 hours and produced 8 cockpits and 12 propulsion systems.

⇒ 8x+12y =56 --b

Solving equation a and b by substitution method

Substitute the value of x from equation in b

⇒ $8(\frac{26-6y}{4}) +12y =56$

⇒ 52-12y+12y =56

⇒ 52 =56

We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.

Answer from: Quest

366

step-by-step explanation:

Answer from: Quest

Lol english

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