The formula t= 2pi sqrt(l/32) relates the time, t, in seconds for a pendulum with the length, l, in feet, to make one full swing back and forth. what is the length of a pendulum that makes one full swing in 2.2 seconds? use 3.14 for pi.

Remark

I like to work from the original equation.

Givens

T = 2.2 seconds

pi = 3.14

L = ??

Substitute and Solve

T = 2*pi*sqrt(L/32) Find the value of 2*pi

2.2 = 2*3.14* sqrt(L/32)

2.2 = 6.28 * sqrt(L/32) Divide both sides by 6.28

2.2/6.28 = sqrt(L/32)

0.35032 = sqrt(L/32) Square both sides.

0.122723 = L/32 Multiply both sides by 32

0.122723 * 32 = L

L = 3.927 feet. <<<<< Length pendulum creating 2.2 seconds.

The length of a pendulum that makes one full swing in 2.2 seconds is 392.71 feet

Given the formula for calculating the length of the pendulum expressed as:

where:

L is the length of the pendulum

T is the period of the pendulum

Given the following parameters:

Period T = 2.2 seconds

Substitute the given parameters into the formula will give;

This shows that the length of a pendulum that makes one full swing in 2.2 seconds is 392.71 feet

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42 inches then 10 1/2 deep

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.