hello dear answer my questoion for math you : )

m<BOA = 360 - 250 = 110 degrees

<BDA = 1/2 (110) = 55 degrees

<BCA = 1/2(250 - 110) = 1/2(140)

<BCA = 70 degrees

AOB = 360 - 250 = 110 degrees

The subtended angle to the arc is half its measure,

BDA = AOB/2 = 55 degrees

The two tangents at A and B make right angles to the radius so the remaining angles in the quadrilateral OBCA are supplementary.

BCA = 180 - AOB = 180 - 110 = 70 degrees

BDA = 55° and BCA = 70°

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