How would i do this problem? in trapezoid pqrs, pq is parallel to sr. find the area of pqrs. leave your answer is simplest radical form.

Suppose that the altitude drawn intersects the base of PQRS at point T

With triangle RTQ, we see that angle T is 90° and angle R is 30°. Since the angles in a triangle always sum to 180°, angle Q is 180° - 90° - 30° = 60°. Thus, triangle RTQ is a 30°-60°-90° right triangle.

The sides of a 30°-60°-90° triangle are in ratio 1:√3:2 (this is in the form (side opposite to 30° angle):(side opposite to 60° angle):(side opposite to 90° angle)). The hypotenuse, the side opposite opposite to the 90° angle, has a length of 24. The altitude of the triangle, the side opposite to the 30° angle, therefore has a length of 24/2 = 12; and the base of the triangle, the side opposite to the 60° angle, has a length of 12√3

Therefore, the area of PQRS is

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