If sin theta = 2/3 and tan theta < 0, what is the value of cos theta? a) sqrt 5/2 b) -sqrt 5 c) sqrt 5/3 d) -sqrt 5/3

It is given tan theta <0

we know that tan theta is negative ( OR <0 ) in second ( pi/2 to pi )and fourth quadrant ( from 3pi/2 to 2 pi ) only .

Given sin theta = 2/3 which is positive ( first and second quadrant ) value so we can consider second quadrant only

Second quadrant tan( theta ) is <0 and sin( theta ) >0

We know sin ^2 ( theta) + cos^2( theta) = 1

( 2/3) ^2 + cos^2( theta ) = 1

Cos^2 (theta ) = 1- ( 2/3)^2

Cos^2 ( theta ) = 1- (4/9)

Cos^2 (theta ) = ( 9-4) / 9

Cos^2 theta = 5 /9

Cos theta = sqrt 5/3 OR - sqrt 5 /3

BUT Cos is negative in second quadrant

So answer is - sqrt 5/ 3

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

answer: 414,377,008

step-by-step explanation:

just multiply it