Solve the inequality l 3x + 6l < 12

In this question , we have to solve the given inequality question.

When removing the absolute sign , we will get a compound inequality which is

-12<3x+6<12

Now whatever we do in the middle, we have to do to both sides.

First we get rid of 6, and for that, we subtract 6

-12-6<3x+6-6<12-6

-18<3x<6

Now we need to get rid of 3, and for that we divide whole inequality by 3, that is

-6<x<2

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i dont know

step-by-step explanation: