An airplane flies 810 km in 1.5 hours. how far will the plane fly into. two hours if it maintains the same airspeed

It would help to first find the unit rate. We know that the plane flies 810 km per 1.5 hours. Divide by 1.5 on both sides:

810/1.5 = 540 km/hour

Then, multiply both the hour and the distance by 2:

540 * 2 = 1080 km/2 hours.

rounding to the nearest thousandth would be 452,000

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: