Given y=x+4 and y=x^2 +4x, find x and y.

y=x+4 ...............(1)

...........(2)

plugging value of y from (1) in (2)

from here we get two values of x as

x-1=0, x=1 and x+4=0, x=-4

plugging x=1 in equation (1)

y=x+4 =1+4=5

plugging x=-4 in equation (1) , we get

y=x+4 =4-4 =0

so for x=1, y=5 and x=-4, y=0

x=1, y=5 and x=-4, y=5 points are (1,5) and (-4,5)

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)

if you would like with a question it is easy to get an answer by including some or multi choice options

step-by-step explanation: