Answer will give a rectangle has a perimeter equal to 24. if we consider its width x, how could we talk about its length y in terms of x? what are possible values of x? what are possible values of y? y= width is= length is=

If the width is x, we count x twice since there are two widths in a rectangle. The perimeter is: 24 = 2x + 2y.

That means that 2y = 24 - 2x

and

y = 12 - x

x obviously has to be greater than 0, but to make sure that y is not zero and positive, we look at the equation y = 12 - x to determine possible values of x. The greatest possible value of x is 11, so: 0 < x < 11.

If we look back at our equation: 24 = 2x + 2y, we see that we can write it as:

2x = 24 - 2y or

x = 12 - y

We can use the same explanation we used to find the possible values of x to find the possible values of y: 0 < y < 11

So, the three answers are:

y = 12 - x

width is: 0 < x < 11

length is: 0 < y < 11

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]