Children and adult tickets were sold for a local play. the children and adult tickets sold for $11 and $16, respectively. of 150 tickets were sold, and the total revenue was $2250 for the night, find the number of children and adult tickets sold.

Given:

1. Children ticket = $11 , Adult ticket = $16

2. Total tickets sold = 150

3. Total revenue = $2250

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Assumed all sold are children tickets:

total revenue = 150 x 11 = $1650

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Difference in revenue:

$2250 - $1650 = $600

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Difference in the price of two tickets:

$16 - $11 = $5

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Find number of adult tickets:

Number of adult tickets = $600 ÷ $5 = 120

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Find number of children tickets:

Number of children tickets = 150 - 120 = 30

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Adult tickets = 120, Children tickets = 30

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!