Astadium has central rectangular area 125m long by 80 m wide there are two semicircular ends. running tracks goes all way round

) Using formula for cicumference.

Circumference = Pi * diameter

Circumference = Pi * 80m

Circumference = 251.2m.

Total inside length of the curved ends.

2)Total distance round inside of track =

2(125) + 251.2m

= 250 + 251.2

= 501.2m

3) Area of circular ends =

Pi*r^2

= Pi*40^2

= 5024m^2

Area of central area (rectangle)

length * width

125m * 80m

= 10,000m^2

Total area inside track =

5,024m^2 + 10,000m^2

= 15,024m^2

Hope this helps.

:-)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

they go with it happens or they mite give a chance?

step-by-step explanation: