True or false? in o, radius op intersects chord ac in point b so that ab = 2 units and bc = 4 units. this means that op is perpendicular to ac.

Answer

FALSE

Explanation

OP is the radius of the circle. It can be perpendicular to the any chord it in two equal part.

In the this case, OP does not divide it equally. So, it is not a perpendicular to the chord AC.

It is False .i.e., OP is not perpendicular to AC

Step-by-step explanation:

Given: AC is chord , OP is radius and OP & AC intersects at B

           AB = 2 units , BC = 4 units

To find: True or False : OP is perpendicular to AC

AB = 2 unit and BC = 4 unit

⇒ AB ≠ BC

But We know Perpendicular drawn from center bisect the chord or a line from center which bisect the chord is perpendicular to it.

⇒ Line OP is not perpendicular to the given chord AC as it is not bisecting the chord.

Figure is attached.

Therefore, It is False .i.e., OP is not perpendicular to AC

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5