Assume that a randomly selected subject is given a bone density test. those test scores are normally distributed with a mean of 0 and a standard deviation of 1. find the probability that a given score is less than 2.23 and draw a sketch of the region.

The randomly selected subject is given bone density test which are normally distributed with mean =0 and standard deviation =1. It means bone density test score is standard normal variable.

The probability that a given score is less than 2.23

P(z < 2.23)

Using z score table to find probability below z=2.23

P(z < 2.23) = 0.9871

The probability that a given score is less than 2.23 is 0.9871

add an image, and i will answer

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the answer i believe is 27 units.

step-by-step explanation: