Explain the difference between using the trigonometric ratios (sin, cos, tan) to solve for a missing angle in a right triangle versus using the reciprocal ratios (sec, csc, cot). you must use complete sentences and any evidence needed (such as an example) to prove your point of view.

it is often convenient to solve for angles in terms of the standard trigonometric ratios (sin, cos, tan) because most scientific and graphing calculators support the inverse functions of those ratios. that is, they give angle measures from trig ratio values. however, with appropriate calculator support, it doesn't matter which ratios you choose to work with. the first picture gives an example of a calculator with inverse trig functions of only sin, cos, and tan. the second picture shows a calculator with inverse trig functions of all of the trig ratios.

the answer is a reflection across the line m

step-by-step explanation:

on edge

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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