Mei throws a snowball from a starting height of 10 feet, with an initial velocity of 12 feet per second. which of the following equations shows the path of the snowball? h(t) = −16t2 + 12t + 10 h(t) = −16t2 + 10t + 12 h(t) = −16t2 + 22t h(t) = −16t2 + 22

The form of the equation for ballistic motion with units in feet and seconds is

Your problem statement tells you the initial velocity v₀ is 12 ft/s and the initial height h₀ is 10 ft. Substituting these values into the form above gives

... H(t) = -16t² +12t +10 . . . . . . corresponds to the 1st selection

A is correct.

Step-by-step explanation:

Mei throws a snowball from a starting height of 10 feet.

We have motion equation if throws up

where,

We need to find the the path of snowball whose initial height 10 feet and initial velocity is 12 feet per second.

Substitute h and v into formula

Hence, The path of snowball is

me! what did you put for this question?

step-by-step explanation:

addition

step-by-step explanation: