Pr equals 12 p q equals 8 sq is greater than t q and st equals 18 find tq

PR =12 and PQ =8. Therefore QR=12-8=4

And ST=18

Let SQ=x,then TQ=18-x

Here we have to use the chord intersection formula, which is

PQ*QR = SQ*TQ

8*4 = x(18-x)

Distributing x on 18-x

(x-16)(x-2)=0

x-16=0 , x-2=0

x=16,x=2

So SQ =16 and TQ=18-16=2

Therefore the answer is 2 .

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x