The area of a rectangle is 55 ft squared , and the length of the rectangle is 4 ft less than three times the width. find the dimensions of the rectangle. {algebra 1 }

W = width

Length is 4 ft less than three times the width L = 3W - 4

A = L x W

55 = (3W - 4)(W)

55 = 3W^2 - 4W

3W^2 - 4W - 55 = 0

(3W + 11)(W - 5) = 0

Width can't be negative so

W - 5 = 0; W = 5

L = 3W - 4 = 3(5) - 4 = 11

Length = 11 ft

Width = 5 ft

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.