Aright triangle has the following. ab=20, ac=99, cb=101. sin b=? , cos b=? , tan b=? reduce your answers as fractions if possible

The editor is doing strange things. I have to start over.

Are we working with a right triangle?

Use a^2 + b^2 = c^2 to find out. The right angle is opposite <A. So the equation becomes b^2 + c^2 = a^2. (a is the longest line and hence it is the hypotenuse.

b= 99

c = 20

a = 101

99^2 + 20^2 = 101^2

9801 + 400 = 10201 but 101^2 = 10201 so we are working with a right angle triangle.

Find the trig functions.

Sin(B) = opposite / hypotenuse = AC/BC = 99/101

Cos(B) = adjacent / hypotenuse = AB / BC = 20/101

Tan(B) = opposite / adjacent = AC/AB = 99/20

If these are not your answers, try putting in the decimal form

Sin(B) = 0.9802

Cos(B) = 0.1980

Tan(B) = 4.95

2 over 5 and 4 over 15

don’t know last one sorry

step-by-step explanation:

step-by-step explanation:

hihi so drawing these 2 triangles is fairly simple. all that's left is finding the height of each one. luckily, we have a side length and an angle, so there is a trig function we can use to solve for the height. the easiest one to use would be tangent, since we have 2/3 things needed to find and the third needed is what we are solving for. tan(73°) * 30 ~= 98.13 and tan(73°) * 35 ~= 114.45