In the diagram, p1p2 and q1q2 are the perpendicular bisectors of bar(ab) and bar(bc), respectively. a1a2 and b1b2 are the angle bisectors of angle a and angle b respectively. what is the center of the circumscribed circle of deltaabc?

For a better understanding of the question please check the attached diagram.

As can be clearly seen from the diagram, the point of intersection of the perpendicular bisectors of the sides of the triangle is the point P and we know that the center of the circumscribed circle of a triangle is the point of intersection of the perpendicular bisectors of its sides.

Thus, using these two pieces of information we can conclude that the Point P is the center of the circumscribed circle of .

87%

step-by-step explanation:

apex answer

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl