The graph represents function 1, and the equation represents function 2: function 2 y = 8x + 12 how much more is the rate of change of function 2 than the rate of change of function 1? 3 4 5 8

Function 1 is the graph of a horizontal line. And the rate of change of a horizontal line is always 0 because there's is no change of y's.

So, rate of change of function 1= 0.

Slope intercept form of a line is y=mx+b where m= rate of change and b= -intercept.

By comparing the given function 2: y= 8x+12 with y=mx+b we will get m= 8.

So, rate of change of function 2= 8

Difference of rate of change of function 2 with 1 = 8-0= 8

So, the rate of change of function 2 is 8 more than the rate of change of function 1.

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

only 10/60 isn't equivalent

hope this : )