Mathematics, 14.07.2019 12:30 zoolo1
Solve 1 over 36 = 6x−3. (1 point) x = −5 x = negative 3 over 2 x = 7 over 2 x = 1
Answers: 1
and calculate its value, as following:![log(\frac{1}{36} )=log6^{(x-3)} \\ log(\frac{1}{36} )=(x-3)log(6)\\ x=[\frac{log(\frac{1}{36} )}{log(6)} ]-3\\ x=1](/tpl/images/0088/6477/fe251.png)
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Solve 1 over 36 = 6x−3. (1 point) x = −5 x = negative 3 over 2 x = 7 over 2 x = 1...
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