Which point is on the circle described by (x - 2)^2 + (y + 3)^2 = 4? (0, 0) (2, 0) (2, -5) (1, -4)

The point that would appear on the circle is (2, -5).

We can find this by using the values in the equation given. So, let's start with the equation.

(x - 2)^2 + (y + 3)^2 = 4

Now we add in our values for x and y.

(2 - 2)^2 + (-5 + 3)^2 = 4

And now we can solve and look for a true statement. If the statement is true at the end, we know it was on the line.

(2 - 2)^2 + (-5 + 3)^2 = 4

(0)^2 + (-2)^2 = 4

0 + 4 = 4

4 = 4 (TRUE)

0/5 is 0, 2/0 is undefined, and 0/0 is indeterminate.

step-by-step explanation:

hope my answer has you!

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!