Write an equation of the line that is perpendicular to the line 5y=x-5 through the point (-1,0)

Your line in slope-intercept becomes:
y = 1/5x -1

A line that is perpendicular to that has the negative reciprocal slope of the given slope which becomes:
-5

Place the given point in the y=mx+b for x and y. to find b:
0=-5(-1) + b
0=5 +b
-5 = b

Therefore, your equation/answer is:
y = -5x -5

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