Need here . 6.06 solve the triangle. a = 33°, a = 20, b = 13 (1 point) cannot be solved b = 20.7°, c = 146.3°, c ≈ 23.7 b = 20.7°, c = 126.3°, c ≈ 17.8 b = 20.7°, c = 126.3°, c ≈ 29.6 2. state whether the given measurements determine zero, one, or two triangles. c = 30°, a = 32, c = 16 (1 point) two zero one 3. two triangles can be formed with the given information. use the law of sines to solve the triangles. a = 59°, a = 13, b = 14 (1 point) b = 22.6°, c = 98.4°, c = 15; b = 157.4°, c = 81.6°, c = 15 b = 67.4°, c = 53.6°, c = 13.8; b = 112.6°, c = 8.4°, c = 13.8 b = 22.6°, c = 98.4°, c = 11.3; b = 157.4°, c = 81.6°, c = 11.3 b = 67.4°, c = 53.6°, c = 12.2; b = 112.

1. Solve the triangle. A = 33°, a = 20, b = 13 (1 point)

The supplement of B (which has the same sine) is around 159° so with A exceeds 180 degrees so we ignore it.

Fourth choice: B = 20.7°, C = 126.3°, c ≈ 29.6

2. State whether the given measurements determine zero, one, or two triangles. C = 30°, a = 32, c = 16 (1 point)

That's unique, A=90°

One triangle.

3. Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 59°, a = 13, b = 14 (1 point)

There are two triangle angles with this sine, supplementary to each other,

Since when combined with A=59° neither A+B exceeds 180°, we have two valid triangles.

That's the last choice, suitably edited:

B = 67.4°, C = 53.6°, c = 12.2; B = 112.6°, C = 8.4°, c = 2.2

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