Given:   `deltaabc`  with  `bar(de)`  ||  `bar(ac)`  prove:   `(ad)/(db) = (ce)/(eb)`statementreason1.  `bar(de)`  ||  `bar(ac)`given2.  `/_ cab~=/_edb`        `/_acb~=/_deb`if two parallel lines are cut by a transversal, the corresponding angles are congruent.3.  `deltaabc ~ deltadbe`aa criterion for similarity4.  corresponding sides of similar triangles are proportional.5.  ab = ad + db      cb = ce + ebsegment addition6.  `(ad + db) /(db) = (ce + eb) /(eb)`substitution property of equality7.  `(ad)/(db) + 1 = (ce)/(eb) + 1`division8.  `(ad)/(db) = (ce)/(eb)`subtraction property of equalitywhat is the missing statement in the proof?   scroll down to see the entire proof.