The length of a rectangle is four times the width. the perimeter of the rectangle is 45 inches. write a system of equations that represents this problem. what is the area of the rectangle?

Let the width of that rectangle be 'b'then, it's length according to question would be 4b.now,the perimeter of given rectangle = 45 inches.as perimeter of a rectangle = 2 (length + breadth)in our case it becomes,2(b +4b) = 45 10b = 45b = 45/5 = 4.5therefore,breath = b = 4.5 inchesand length = 4b = 4(4.5)= 18 inches.area of a rectangle = length × width so, the area of given triangle = 4.5 × 18= 81 inches square.

All about the same size in the city the game was