3(x-5)< =30how do you solve this problem

The way that it is written is odd.

If the problem was 3(x-5)=30, it would be 3x-15=30.

Add 15 to both sides.

3x=45

Divide both sides by 3.

x=15

If it's supposed to be 3(x-5)<30, your answer would be the same, except:

x<15.

I'm not sure why it has both signs, especially next to each other.

I hope this helps :)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}