Graph the parabola y equals negative x squared + 3 to graph a parabola plot the vertex and four additional points two on each side of the vertex then click on the graph icon

You don't have the graph icon here, so we'll have to graph this parabola without it.

Your parabola is y = -x^2 + 3., which resembles y = a(x-h)^2 + k. We can tell immediately that this parabola opens down and that the vertex is (0,3).

Plot (0,3). Besides being the vertex, this point is also the max. of the function.

Now calculate four more points. Choose four arbitrary x-values, such as {-2, 1, 4, 5} and find the y value for each one. Plot the resulting four points. Draw a smooth curve thru them, remembering (again) that the vertex is at (0,3) and that the parabola opens down.

okay wait before i answer, is this for your points on a graph?