Amath teacher claimed that the average grade of the students in her algebra 2 classes this year would be equal to the average grade of the same students in algebra 1 classes last year. the average grade of last year’s algebra 1 students was an 87%. in a random sample of 30 current algebra 2 students, the average grade was 86%, with a standard deviation of 3%. is there enough evidence to reject the teacher's claim? enter your answer as a z-value and either yes or no, separated by a comma, like this: -4.25, yes

These questions should be asked more clearly.

If 3% is the standard deviation of the average then a 1% decrease in score is a z=-1/3, which is small in absolute value, so we can't reject the claim. In this interpretation we'd -0.33, no.

But if we'll assume 3% is the standard deviation of the individual samples, it's a different story. We use percent as our unit. The standard deviation of the average is

.

So we get a z (really a t) here of

That's kinda borderline, a one sided t test with 29 dfs will give about the same probability as the normal distribution for a tail z=1.8, p=.036 aka p=3.6%. Typically we'd choose a 1% or 5% rejection threshold before we started; this one is in between.

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1