The hull of a ship should be the only portion of a ship that is below the water. therefore, at a minimum, how many tons of sea water should the hull of the titanic displace while it’s in water?

Hi,

This is conceptual question;

Concept: This is based on Archimedes's Principle. According to this principle, when an object is partially or fully submersed in a given liquid then it displaces the equal amount of liquid that it has lost in its weight.

Consider hull of Titanic Ship has weight 'w' and area of base is 'A'. If ρ be the density of water. Let 'h' be the height of hull then the pressure exerted by hull at the surface of water 'P'.

The upthrust at the bottom of the ship is given as

F = Vρg

F=Ahρg

Hence the required weight of water should be more than the Ahρg.

Here, density of water(ρ) = 1000 kg /m^3, the value of g=9.8 m/s^2.

If A= 100 m^2 and h = 30 m then required mass of water

m = F/g

m=Ahρg /g

or,

or, m = 3, 000,000 kg

or, m = 3,000 tons water is required.

The hull should displace sea water as much as : density of sea water x volume of immersed hull(ρf x Vh)

Archimedes states that the buoyant force acting on an object which is partially or completely immersed into a fluid is equal to the weight of the fluid displaced by the object

Buoyancy can be formulated

Fb = floating force

ρf = fluid density, kg / m3

Vf = volume of objects immersed in fluid

If the object is completely immersed, Vf = the volume of the object ,Vo

There are 3 conditions that occur in an object in a fluid that is floating, in the middle of the fluid and sink

Floating if the density of an object <the density of a liquid , ρo < ρf

in the middle of a fluid if the density of a liquid is the density of an object , ρf = ρo

sink if the density of an object> the density of a liquid , ρo > ρf

In the state of the hull of a ship is below the water, the ship's condition is in a floating condition.

In this situation, there is a balance between the buoyancy force and the weight of the object

ρs. Vs. g = ρf. Vh. g

rho s = density of ship

Vs = the volume of the ship

Vh = the volume of immersed hull

So the fluid mass, Mf (in this case sea water) that is moved (displaced) by the ship is:

Isaac Newton's investigations of gravity

link

Gravitational force

link

increase the gravitational force between two objects

link

one that is bigger than 3 1/2

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5