Aparabola with a vertex (1,5) and y-intercept (0,2) crosses the x-axis in two places. one x-intercept is at (-0.29,0) what is the other x-intercept?

The other x intercept would be 2.29.

You can find this by first modeling the equation using vertex form: y = a(x - h)^2 + k, in which the variables stand for the following:

a = constant

h = x value of vertex

k = y value of vertex.

Since we know enough to plug in and solve for a, we can get the equation we are using.

y = a(x - h)^2 + k

First put in the vertex points into (h, k)

y = a(x - 1)^2 + 5

Now add the points we know for x and y from the y-intercept

2 = a(0 - 1)^2 + 5

And solve that for a

2 = a(0 - 1)^2 + 5

2 = a (-1)^2 + 5

2 = a + 5

-3 = a

Now we can model the equation as y = -3(x - 1)^2 + 5. Using that, we can distribute to put in standard form.

y = -3(x - 1)^2 + 5

y = -3(x^2 - 2x + 1) + 5

y = -3x^2 + 6x - 3 + 5

y = -3x^2 + 6x + 2

Now we can use the quadratic equation to solve for the remaining zero. Using the following variables:

a = -3 (attached to x^2)

b = 6 (attached to x)

c = 2 (constant)

x = 0.29 or x = -2.29

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!