An object is launched at 25 m/s from a height of 80 m. the equation for the height (h) in terms of time (t) is given by h(t)=4.9t^2+25t+80. what's the objects maximum height?

There must be minus sign with 4.9 .

The given equation is the equation of parabola , which is maximum at its vertex, and the formula of vertex is

So the height is maximum at t=2.55 seconds and to find the maximum height , we need to plug 2.55 for t , that is

So the maximum height is 112 m .

chase is right because he already been to the swings and he know how far it will be to get there

step-by-step explanation:

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2