The number of lightning strikes in a year at the top of a particular mountain has a poisson distribution with a mean of 3.8. find the probability that in a randomly selected year, the number of lightning strikes is 0.

Let X be the number of lightning strikes in a year at the top of particular mountain.

X follows Poisson distribution with mean μ = 3.8

We have to find here the probability that in randomly selected year the number of lightning strikes is 0

The Poisson probability is given by,

P(X=k) =

Here we have X=0, mean =3.8

Hence probability that X=0 is given by

P(X=0) =

P(X=0) =

P(X=0) = 0.0224

The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation:

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