Find the linearization l(x) of the function at a. f(x) = x4 + 4x2, a = 1

The formula of linearization is

L = f(a)+f'(a)(x-a)

We have

And it is given in the question that a=1.

So f(a) = f(1) = 1+4=5

Now we need to find f'(a) and for that , first we need to find f'(x).

At a=1,

Substituting the values of f(1) and f'(1) in the linearization formula

L=5+12(x-1)

L= 5+12x-12

L= 12x -7

And that's the required linearization .

step-by-step explanation:

no solution.

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