Two samples each of size 25 are taken from independent populations assumed to be normally distributed with equal variances. the first sample has a mean of 35.5 and standard deviation of 3.0 while the second sample has a mean of 33.0 and standard deviation of 4.0. the pooled estimate of the common variance is 12.5. what is the value of the computed test statistic for testing the equality of the population means

Pooled Combined Variance

Test Statistic:

Degrees of freedom =

The table value is greater than the calculated value.

Thus we accept H0.

7,24

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;