The graph of the even function f(x) has 5 x-intercepts if (6,0) is the one of the intercepts what set of points can be the other intercepts of the graph of f(x)? ,0) , (-2,0) ,and (0,0),0) , (-2,0) , and (4,0),0) , (0,0) , and (2,0),0) , (-2,0) , and (0,0)

f(x) being even means

f(x) = f(-x)

So the zeros come in positive and negative pairs. If there are an odd number of intercepts like there are here, it's because one of them is x=0 which is its own negation.

Given zero x=6 we know x=-6 is also a zero.

So we know three zeros, and know the other two zeros are a positive and negative pair.

The only choice with (-6,0) and (0,0) is A.

Choice A

good luck on your studies! : )

david edward.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!