One box office of a movie theater sold 86 tickets more than the other one. how many tickets were sold by each box office, if the total number of tickets sold was 792?

According to the question, we have two box offices  which can be represented as:

A

B = Box office that sold 86 more tickets A. This statement is represented algebraically as : A + 86

The total number of tickets sold = 792

Hence, our Algebraic expression = A + B = 792

Note: B = A + 86

A + A + 86 = 792

2A + 86 = 792

Collect like terms

2A = 792 - 86

2A = 706

Divide both sides by 2

2A/2 = 706/2

A = 353 tickets

Solving for B

B = A + 86 = 353 + 86

B = 439 tickets

Therefore,

Box office A sold 353 tickets

Box office B sold 439 tickets

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353 and 439 tickets.

Step-by-step explanation:

Total number of tickets sold = 792

Let Box office one sold tickets be x

Box office two sold tickets = x + 86

Total tickets sold = x + (x+86) = 792

                            = 2x + 86 = 792

                            = 2x = 792 - 86

                            = 2x = 706

                               x = 353

One box office sold 353 tickets, As per given statement that "second box office sold 86 more tickets"

Box office two sold 353 + 86 = 439 tickets

Therefore, one box office sold 353 and other box office sold 439 tickets.

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step-by-step explanation:

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