Ten pieces of paper numbered consecutively from 1 to 10 are put into a hat. if three pieces of paper are drawn at random from the hat one at a time without being returned to the hat, what is the probability that all three will be even numbers

There are 5 even numbers from 1 to 10.

The number of ways to draw all even numbers is 5!/(2!*3!) = 10

The number of ways to draw from the hat is 10!/(7!*3!) = 128

Therefore the probability is 10/128 = 5/64 or roughly 7.81%

the one on the bottom left

step-by-step explanation:

all of the other ones have a specific pattern

22 and 22

step-by-step explanation:

10 plus 12 equals 22.

12 plus 10 also equals 22 because regardless of what order they're in, they're gonna equal the same thing.