[will mark as brainliest] what is the inverse of the function below? f(x) = 2^x + 6 a.) f^-1(x) = 6 + log2x b.) f^-1(x) = log2(x + 6) c.) f^-1(x) = 6log2x d.) f^-1(x) = log2(x - 6)

What is the inverse of the function below?

f(x) = 2^x + 6

1) Replace "f(x)" with "y" y = 2^x + 6

2) Interchange x and y: x=2^y + 6

3) Solve this for y: 2^y = x - 6 Take the log to the base 2 of both sides:

y = (log to the base 2 of) (x-6)

4) replace y with

-1

f (x)

We obtain:

-1

f (x) = (log to the base 2 of) (x-6)

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.