Determine the equation of a line that passrs through the point (4,-1) and also parallel to y=3x+4

First, plug in the given point into y=mx +b to find b (the y-intercept of the line). Use the same slope (m) in the equation since parallel lines have the same slope (3 in this case).

-1 = 3(4) +b
-1 = 12 + b Subtract 12 to both sides.
-13 = b

Now, put your m and b into y=mx+b.

The final answer/equation of your line is:

y=3x -13

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