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Mathematics, 15.07.2019 03:00 apodoltsev2021

Solve 64^x = 16^xβˆ’1. 1. x = βˆ’2 2 x = βˆ’1 3. x = - 1 /4 4. x = negative 1 over 3

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Solve 64^x = 16^xβˆ’1. 1. x = βˆ’2 2 x = βˆ’1 3. x = - 1 /4 4. x = negative 1 over 3...
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