Need asap the area of a parking lot is 600 square meters. a car requires 6 square meters. a bus requires 30 square meters. the attendant can handle only 60 vehicles. if a car is charged $2.50 and a bus $7.50, how many of each should be accepted to maximize income?

The answer is simple:

Constraints:

C > 0, B > 0 their both greater than equal to if your wondering if it does not fit

C + B < 60 less than equal to

6c + 30 b < 600 less than equal to

Profit:

P( c, b) = 2.5c + 7.5 b

Answer is 50 cars and 10 buses, hope this helps and pls. give me brainliest if I deserved it!!

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5