Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).

Answer

y = (-1/3)x - 3

Explanation

To get the equation of a line we need; gradient of that line and and a point that lies on that line.

Firstly, we find the midpoint to get the point that lies on the required equaion.

midpoint = ((4+2)/2 , (1+ -5)/2)

= (6/2, -4/2)

= (3, -2)

Secondly, we find the gradient of the line.

gradient = Δy/Δx

= (1- -5)/(4-2)

= 6/2

= 3

The products of gradients of perpendicular line is -1.

∴ m₁ ₓ m₂ = -1

3 ₓ m₂ =-1

m₂ = -1/3

Now that we have the gradient and the point, we can find the equation a follows:

-1/3 = (y - -2)/(x-3)

-1(x-3) = 3(y+2)

-x + 3 = 3y +6

3y = -x - 3

y = (-1/3)x - 3

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!