Plz answer which statements are true about the graph of the function f(x) = 6x – 4 + x2? check all that apply. the vertex form of the function is f(x) = (x – 2)2 + 2. the vertex of the function is (–3, –13). the axis of symmetry for the function is x = 3. the graph increases over the interval (–3, ). the function does not cross the x-axis.

We complete the square to get vertex form.







The vertex form of the function is f(x) = (x – 2)2 + 2.

Nope.

The vertex of the function is (–3, –13).

Yes, that's easily seen from the vertex form we got.

 The axis of symmetry for the function is x = 3.

Nope, x = -3 is the symmetry axis.

 The graph increases over the interval (–3, infinity).

That's true; the minimum is at the vertex when the squared term is zero and it increases both ways from there.

The function does not cross the x-axis.

No, it does cross; its minimum is -13 and it goes up from there.

The answer is 1 because you have to flip the sign when dividing by negative number and 3

Do the inverse operation