We can show that ∆abc is congruent to ∆a′b′c′ by a translation of unit(s) and a across the -axis.

We can show that ΔABC is congruent to ΔA'B'C' by a translation of 2 unit(s) Left and a Reflection across the x axis.

Step-by-step explanation:

The given triangles ABC and A'B'C' are congruent.

If we take a point A of ΔABC and A' of ΔA'B'C' then we get the coordinates of A as (8,8) and A' (6,-8)

Therefore, shifting of A to A' = (8_6) = 2 unit on x axis and no translation in  y-coordinates.

So translation of 2 units left has occurred.

In addition to this ΔABC is reflected by x-axis to form A'B'C'.

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

b.my answer is b.

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